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poj1008(Maya Calendar)玛雅历(c++实现)
发布时间:2023/12/18
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poj1008(Maya Calendar)玛雅历(c++实现)
小编觉得挺不错的,现在分享给大家,帮大家做个参考.
这道题目不难,就是简单的模拟算法。但是还是给了我一个教训,就是以后看题要仔细仔细,
因为刚开始老是评测不能过,后来发现是少输出了个日期数,就是一开始把日期数输入了,然后把他输出一遍就可以了。
1、
2、改进:把一维字符串数组改为二维的字符数组,将cin、cout改为scanf、printf。
效率提高了不少。耗时0s,内存为160k。不过与排名靠前的0s,8k,还是有很大距离。
如果大家有什么好方法,请指教,谢谢!
改进后代码:
#include<stdio.h> #include<iostream> using namespace std; #include<string> int main() {int k,n,i;int day,year;char month[19][7]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};char month1[20][9]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};char mon[7];scanf("%d",&k);printf("%d\n",k);while (k--){scanf("%d.%s%d",&day,mon,&year);for (i=0;i<19;i++)if (!strcmp(mon,month[i])) n=20*i;n=year*365+n+day+1;year=(n-1)/260;if (n%260==0) n=260;else n=n%260;if (n%13==0) day=13;else day=n%13;if (n%20==0) n=20;else n=n%20;printf("%d %s %d\n",day,month1[n-1],year);} return 0; }总结
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