欢迎访问 生活随笔!

生活随笔

当前位置: 首页 > 编程资源 > 编程问答 >内容正文

编程问答

PAT甲级 -- 1041 Be Unique (20 分)

发布时间:2024/2/28 编程问答 41 豆豆
生活随笔 收集整理的这篇文章主要介绍了 PAT甲级 -- 1041 Be Unique (20 分) 小编觉得挺不错的,现在分享给大家,帮大家做个参考.

Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1,10​4​​]. The first one who bets on a unique number wins. For example, if there are 7 people betting on { 5 31 5 88 67 88 17 }, then the second one who bets on 31 wins.

Input Specification:

Each input file contains one test case. Each case contains a line which begins with a positive integer N (≤10​5​​) and then followed by N bets. The numbers are separated by a space.

Output Specification:

For each test case, print the winning number in a line. If there is no winner, print None instead.

Sample Input 1:

7 5 31 5 88 67 88 17

Sample Output 1:

31

Sample Input 2:

5 888 666 666 888 888

Sample Output 2:

None

AC:

#include <iostream> #include <cmath> #include <vector> using namespace std;int n; struct number {int id, num; }nn; int mx = -1; bool flag = false; int arr[100000+5] = {0}, num; vector<number> v;int main() {scanf("%d", &n);for(int i = 0; i < n; i++){scanf("%d", &num);nn.id = i;nn.num = num;v.push_back(nn);arr[num] += 1;}for(int i = 0; i < v.size(); i++){if(arr[v[i].num] == 1){printf("%d", v[i].num);flag = true;break;}}if(!flag) printf("None");return 0; }

 刚开始打算用数字下标记录,忽略了顺序,后面改为vector,ok了

总结

以上是生活随笔为你收集整理的PAT甲级 -- 1041 Be Unique (20 分)的全部内容,希望文章能够帮你解决所遇到的问题。

如果觉得生活随笔网站内容还不错,欢迎将生活随笔推荐给好友。