基础数据类型上机题

机试题

lis = [['哇',['how',{'good':['cd',1000,'99']},'大帅哥'],'I']] （总分2分）

• 列表lis中的'cd'全部变成大写。(1分)

• 列表中的1000通过数字相加在转换成字符串的方式变成'10086'。(1分)

  lis = [['哇',['how',{'good':['cd',1000,'99']},'大帅哥'],'I']] lis[0][1][1]["good"][0] =lis[0][1][1]["good"][0].upper() print(lis) lis[0][1][1]["good"][1] = str(lis[0][1][1]["good"][1]+9086) print(lis)

dic = {'k1':'v1','k2':['alex','sb'],(1,2,3,):{'k3':['2',100,'wer']}} （总3分）

• 将'k3'对应的值的最后面添加一个元素(1,2,3)。(1分)

• 将'k2'对应的值的第2个位置前插入元素{'a'}。(1分)

• 将(1,2,3,)对应的值添加一个键值对key:(1,)。(1分)

  dic = {'k1':'v1','k2':['alex','sb'],(1,2,3,):{'k3':['2',100,'wer']}} dic[(1,2,3)]["k3"].append((1,2,3)) dic["k2"].insert(1,{"a"}) dic[(1,2,3)].update({"key":(1,)}) print(dic)

敲七游戏. 从1开始数数. 遇到7或者7的倍数包(含17,27,这种数）要在桌上敲⼀下. 编程来完成敲七. 给出⼀个任意的数字n. 从1开始数. 数到n结束. 把每个数字都放在列表中, 在数的过程中出现7或 者7的倍数（包含17,27,这种数）.则向列表中添加⼀个'咣' 例如, 输⼊20.

lst = [1, 2, 3, 4, 5, 6, '咣', 8, 9, 10,11,12,13,'咣',15,16,'咣',18,19,20]

while True:s = input("请输入一个正整数:")if s.isdecimal() and int(s)>0:lst = []for i in range(1,int(s)+1):if i % 7 == 0 or "7" in str(i):lst.append("咣")else:lst.append(i)print(lst)breakelse:print("你输入的格式有误,请重新输入!")

完成36选7的操作, 1- 50之间随机产生36个数,从这36个数中选择7个不重复的数添加到列表中(5分)

from random import randint print(randint(1,20)) # 从1到20之间随机产生1个整数 from random import randint lst = [] for i in range(36):lst.append(randint(1, 50)) lst = list(set(lst))[:7] print(lst)

有文件t1.txt里面的内容为:（5分）

1,alex,22,13651054608,IT 2,wusir,23,13304320533,Tearcher 3,taibai,18,1333235322,IT利用文件操作，将其构造成如下数据类型。 [{'id':'1','name':'alex','age':'22','phone':'13651054608','job':'IT',{'id':'2','name':'wusir','age':'23','phone':'13304320533','job':'Tearcher'},{'id':'3','name':'taibai','age':'18','phone':'1333235322','job':'IT'}] with open("t1.txt","r",encoding="utf-8") as f:lst = f.readlines() lst_job = [] for i in lst:lst1 = i.strip().split(",")dic = {"id":lst1[0],"name":lst1[1],"age":lst1[2],"phone":lst1[3],"job":lst1[4]}lst_job.append(dic) print(lst_job)

有如下车牌和车辆归属地,形成一个新的字典,显示每个归属地的车辆共有多少：(8分)

cars = ['鲁A32444','鲁A12333','湘B8989M','⿊A49678','⿊B46555','沪B25044','冀A11111',"京A01101"] locals = {'冀':{"A":"石家庄","B":"唐山"},'⿊':{"A":"哈尔滨","B":"齐齐哈尔"},'鲁':{"A":"济南","B":"青岛"},'鄂':{"A":"武汉","B":"黄石"},'湘':{"A":"长沙","B":"株洲"},}结果: {'济南':2, '株洲': 1, '哈尔滨': 1,'齐齐哈尔':1,'石家庄':1} cars = ['鲁A32444','鲁A12333','湘B8989M','⿊A49678','⿊B46555','沪B25044','冀A11111',"京A01101"] locals = {'冀':{"A":"石家庄","B":"唐山"},'⿊':{"A":"哈尔滨","B":"齐齐哈尔"},'鲁':{"A":"济南","B":"青岛"},'鄂':{"A":"武汉","B":"黄石"},'湘':{"A":"长沙","B":"株洲"},}dic ={} for i in cars:if i[0] in locals:dic[locals[i[0]][i[1]]] = dic.get(locals[i[0]][i[1]],0)+1 print(dic)

有如下值li 将所有的数字保存至字典的第一个key中，将所有的字符串保存至第二个key的值中(4分)

li= ["a","b",11,22,33,44,55,"66",["alex","baoyuan","taibai"],"77","88","99"] li = ["a","b",11,22,33,44,55,"66",["alex","baoyuan","taibai"],"77","88","99"] dic = {"key1":[],"key2":[]} for i in li:if type(i) ==list:for j in i:if type(j) == int:dic["key1"].append(j)else:dic["key2"].append(j)elif type(i) == int:dic["key1"].append(i)else:dic["key2"].append(i) print(dic)

userinfo.txt 文件中存放以下结构:(总分8分)

alex:alex3714 wusir:123456 meet:meet123

1.让用户选择:

1.注册 2.登录

2.用户选择注册就将账号和密码添加到userinfo.txt中,如果用户名存在就提示用户名存在,不存在就进行添加(2分)

3.用户选择登录,就验证用户的账号和密码是否与userinfo.txt一致,如果一致终止循环提示登录成功(3分)

4.让用户登录三次,三次错误将用户进行锁定提示用户名已锁定,并打印错误次数(使用字符串格式化)(3分)

with open("userinfo.txt ","r",encoding="utf-8")as f1:lst = f1.readlines()dic = {} for i in lst:k,v = i.strip().split(":")dic[k]=v while True:chose = input("请输入你的选择(1.注册 2.登录)\n>>>")if chose == "1":name = input("请输入用户名:")psd = input("请输入密码:")psd1 = input("请再次输入密码:")if name in dic:print("用户名已存在,注册失败!")continueelif psd != psd1:print("两次密码输入不一致,请重新注册!")else:dic[name] = psdprint("注册成功!")with open("userinfo.txt","a",encoding="utf-8")as f2:f2.write(f"\n{name}:{psd}")breakelif chose == "2":count = 3while count :count -=1name2 = input("请输入用户名:")psd2 = input("请输入密码:")if name2 in dic :if psd2 == dic[name2]:print("登陆成功!")breakelse:print("密码错误!")if count:print(f"你还有{count}次机会")else:print("此用户名已锁定!")else:print("账号不存在!")if count:print(f"你还有{count}次机会")else:print("此用户名已锁定!")breakelse :print("请输入正确的选择")

转载于:https://www.cnblogs.com/ciquankun/p/11197576.html

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