python for loop步进值_python-对for循环的结果进行排序时保持值连...

将整个故障单添加到结果列表中,而不只是优先级,然后实施您自己的min函数.另外,根据您的应用程序的其余部分,是否考虑使用与设置结果不同的结构？

# this computes the minimum priority of a ticket

def ticketMin (list):

min = list[0]

for ticket in list:

if (ticket.priority < min.priority):

min = ticket

return min

# changed set to list

result = list()

for ticket in tickets:

# to get rid of the "None" priorities

if ticket.priority != '':

print ""

else:

#notice the change below

result.append(ticket)

# changed 'min' to 'ticketMin'

minTicket = ticketMin(result)

print minTicket.priority

print minTicket.code

另外,您可以保存几行,并将内置函数与Lambda一起使用,如Oscar在注释中所示：

# changed set to list

result = list()

for ticket in tickets:

# to get rid of the "None" priorities

if ticket.priority != '':

print ""

else:

#notice the change below

result.append(ticket)

# Oscar's solution:

minTicket = min(result, key=lambda val : val.priority)

print minTicket.priority

print minTicket.code

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