欢迎访问 生活随笔!

生活随笔

当前位置: 首页 >

HDOJ 1047 Integer Inquiry

发布时间:2025/3/8 33 豆豆
生活随笔 收集整理的这篇文章主要介绍了 HDOJ 1047 Integer Inquiry 小编觉得挺不错的,现在分享给大家,帮大家做个参考.


JAVA睑板....

Integer Inquiry

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12042    Accepted Submission(s): 3037


Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers. 
``This supercomputer is great,'' remarked Chip. ``I only wish Timothy were here to see these results.'' (Chip moved to a new apartment, once one became available on the third floor of the Lemon Sky apartments on Third Street.) 

Input The input will consist of at most 100 lines of text, each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length, and will only contain digits (no VeryLongInteger will be negative). 

The final input line will contain a single zero on a line by itself.

Output Your program should output the sum of the VeryLongIntegers given in the input. 


This problem contains multiple test cases!

The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.

The output format consists of N output blocks. There is a blank line between output blocks.

Sample Input 1 123456789012345678901234567890 123456789012345678901234567890 123456789012345678901234567890 0
Sample Output 370370367037037036703703703670
Source East Central North America 1996


import java.util.*; import java.math.*;public class Main {public static void main(String[] args){Scanner cin= new Scanner(System.in);int n=cin.nextInt();boolean flag=false;while(n-->0){if(flag==false) flag=true;else System.out.println("");BigInteger ans=BigInteger.ZERO;while(cin.hasNextBigInteger()){BigInteger m=cin.nextBigInteger();if(m.equals(BigInteger.ZERO))break;ans=ans.add(m);}System.out.println(ans);}} }


版权声明:本文博客原创文章,博客,未经同意,不得转载。

总结

以上是生活随笔为你收集整理的HDOJ 1047 Integer Inquiry的全部内容,希望文章能够帮你解决所遇到的问题。

如果觉得生活随笔网站内容还不错,欢迎将生活随笔推荐给好友。