欢迎访问 生活随笔!

生活随笔

当前位置: 首页 >

HNUSTOJ-1257 You are my brother

发布时间:2025/3/19 35 豆豆
生活随笔 收集整理的这篇文章主要介绍了 HNUSTOJ-1257 You are my brother 小编觉得挺不错的,现在分享给大家,帮大家做个参考.

1257: You are my brother

时间限制: 1 Sec  内存限制: 128 MB
提交: 39  解决: 15
[提交][状态][讨论版]

题目描述

 

Little A gets to know a new friend, Little B, recently. One day, they realize that they are family 500 years ago. Now, Little A wants to know whether Little B is his elder, younger or brother.

 

 

输入

 

There are multiple test cases.

For each test case, the first line has a single integer, n (n<=1000). The next n lines have two integers a and b (1<=a,b<=2000) each, indicating b is the father of a. One person has exactly one father, of course. Little A is numbered 1 and Little B is numbered 2.

Proceed to the end of file.

 

输出

 

For each test case, if Little B is Little A’s younger, print “You are my younger”. Otherwise, if Little B is Little A’s elder, print “You are my elder”. Otherwise, print “You are my brother”. The output for each test case occupied exactly one line.

 

 

样例输入

5 1 3 2 4 3 5 4 6 5 6 6 1 3 2 4 3 5 4 6 5 7 6 7

样例输出

You are my elder You are my brother
#include<iostream> #include<cstring> #include<cstdio>using namespace std;int pre[2005]; void Solve(){int cnta = 0, cntb = 0, a = 1, b = 2;while(pre[a]){cnta += 1;a = pre[a];}while(pre[b]){cntb += 1;b = pre[b];}if(cnta == cntb) printf("You are my brother\n");else printf("%s\n", cnta < cntb?"You are my younger":"You are my elder"); } int main(){int n;while(scanf("%d", &n) == 1){int a, b;memset(pre, 0, sizeof(pre));for(int i = 0; i < n; i++){scanf("%d %d", &a, &b);pre[a] = b;}Solve();} }

 

 

转载于:https://www.cnblogs.com/Pretty9/p/7406773.html

总结

以上是生活随笔为你收集整理的HNUSTOJ-1257 You are my brother的全部内容,希望文章能够帮你解决所遇到的问题。

如果觉得生活随笔网站内容还不错,欢迎将生活随笔推荐给好友。