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Employee Bonus --leetcode

发布时间:2025/3/20 编程问答 31 豆豆
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2019独角兽企业重金招聘Python工程师标准>>>

leetCode sql没几道题 就开始 收费模式了

Select all employee's name and bonus whose bonus is < 1000.Table:Employee+-------+--------+-----------+--------+ | empId | name | supervisor| salary | +-------+--------+-----------+--------+ | 1 | John | 3 | 1000 | | 2 | Dan | 3 | 2000 | | 3 | Brad | null | 4000 | | 4 | Thomas | 3 | 4000 | +-------+--------+-----------+--------+ empId is the primary key column for this table. Table: Bonus+-------+-------+ | empId | bonus | +-------+-------+ | 2 | 500 | | 4 | 2000 | +-------+-------+ empId is the primary key column for this table. Example ouput:+-------+-------+ | name | bonus | +-------+-------+ | John | null | | Dan | 500 | | Brad | null | +-------+-------+这些被锁的题目 不能在线验证了solution:SELECTEmployee.name, Bonus.bonus FROMEmployeeLEFT JOINBonus ON Employee.empid = Bonus.empid WHEREbonus < 1000 OR bonus IS NULL ;Note: "LEFT OUTER JOIN" could be written as "LEFT JOIN".

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