C语言实现最简单的2048小游戏

网上解释很多了，直接上代码吧，这个功能很简单，易于学习，后期有时间会完善功能

#include<stdio.h> #include<stdlib.h> #include<string.h>#define Key_Up 0x4800 // 向上方向键 　　 #define Key_Down 0x5000 // 向下方向键 #define Key_Right 0x4d00 // 向右方向键 #define Key_Left 0x4b00 // 向左方向键int map[4][4] = { 0 }; int check[4] = { 0 }; //判断游戏是否结束,如果都不为0，游戏结束 int i, j;// //显示在屏幕上 // void print() {for (i = 0; i < 4; i++){for (j = 0; j < 4; j++){printf("%d\t", map[i][j]);}printf("\n");} }// //向右移动 // int moveRight() {int flag = 0; //来标记是否整个map矩阵能否改变，以此判断整个游戏是否结束//这个循环的目的是为了做某一行的加减,如某一行为[2 2 4 4]，经过以下运算就会变为[0 4 0 8];for (i = 0; i < 4; i++){for (j = 4 - 1; j >= 0; j--){int cell = map[i][j];if (cell != 0){int k = j - 1;while (k >= 0){int nextcell = map[i][k];if (nextcell != 0){if (cell == nextcell){flag = 1;map[i][j] += map[i][k];map[i][k] = 0;}k = -1;break;}k--;}}}}//上一步做的是数据加减，这一步对加减后的数据做数据处理//例如某一行经过上一步的数据为【0 4 0 8】，将会变为【0 0 4 8】for (i = 0; i < 4; i++){for (j = 4 - 1; j > 0; j--){int cell = map[i][j];if (cell == 0){int k = j - 1;while (k >= 0){int nextcell = map[i][k];if (nextcell != 0){flag = 1;//当前元素为0，说明能移动，改变flag的值map[i][j] = nextcell;map[i][k] = 0;k = -1;}k--;}}}}if (flag)return 0;elsereturn 4; //游戏结束 }// //向左移动 // int moveLeft() {int flag=0;for (i = 0; i < 4; i++){for (j = 0; j < 4; j++){int cell = map[i][j];//cell单词用的不太恰当，表示当前元素，你可以采用更有意义的命名if (cell != 0){int k = j + 1;while (k < 4){int nextcell = map[i][k];if (nextcell != 0){if (cell == nextcell){flag = 1;//相邻两个元素相同，就说明能移动，所以改变flag的值map[i][j] += map[i][k];map[i][k] = 0;}k = 4;break;}k++;}}}}//修改部分：for循环中的i或者j的循环条件for (i = 0; i < 4; i++){for (j = 0; j < 4 - 1; j++){int cell = map[i][j];if (cell == 0){int k = j + 1;while (k < 4){int nextcell = map[i][k];if (nextcell != 0){flag = 1;map[i][j] = nextcell;map[i][k] = 0;k = 4;}k++;}}}}if (flag)return 0;elsereturn 3; }// //向下移动 // int moveDown() {int flag=0;for (i = 4 - 1; i >= 0; i--){for (j = 0; j < 4; j++){int cell = map[i][j];if (cell != 0){int k = i - 1;while (k >= 0){int nextcell = map[k][j];if (nextcell != 0){if (map[i][j] == map[k][j]){flag = 1;map[i][j] += map[k][j];map[k][j] = 0;}k = 0;break;}k--;}}}}//修改部分：for循环中的i或者j的循环条件for (i = 4 - 1; i > 0; i--){for (j = 0; j < 4; j++){int cell = map[i][j];if (cell == 0){int k = i - 1;while (k >= 0){int nextcell = map[k][j];if (nextcell != 0){flag = 1;map[i][j] = nextcell;map[k][j] = 0;k = 0;}k--;}}}}if (flag)return 0;elsereturn 2; }// //向上移动 // int moveUp() {int flag=0;for (i = 0; i < 4; i++){for (j = 0; j < 4; j++){int cell = map[i][j];if (cell != 0){int k = i + 1;while (k < 4){int nextcell = map[k][j];if (nextcell != 0){if (cell == nextcell){flag = 1;map[i][j] += map[k][j];map[k][j] = 0;}k = 4;break;}k++;}}}}//修改部分：for循环中的i或者j的循环条件for (i = 0; i < 4 - 1; i++){for (j = 0; j < 4; j++){int cell = map[i][j];if (cell == 0){int k = i + 1;while (k < 4){int nextcell = map[k][j];if (nextcell != 0){flag = 1;map[i][j] = nextcell;map[k][j] = 0;k = 4;}k++;}}}}if (flag==0)return 0;elsereturn 1; }// //随机生成在空格上生成2或者4,并且判断是否游戏结束 // int randInteger() //有缺陷，【0 0 0 0】 {for (i = 0; i < 4; i++){for (j = 0; j < 4; j++){if (map[i][j] == 0){map[i][j] = (rand() % 2 + 1) * 2; //return 0;}}}return 0; }int main() {print();char key;while (1){printf("上：w;下：s;左:a;右：d;退出:q\n");printf("请输入要执行的操作:");scanf("%c", &key);switch (key){case 'w':{randInteger();moveUp();printf(" 向上方向键被按下\n");print();break;}case 's':{randInteger();moveDown();printf(" 向下方向键被按下\n");print();break;}case 'a':{randInteger();moveLeft();printf(" 向左方向键被按下\n");print();break;}case 'd':{randInteger();moveRight();printf(" 向右方向键被按下\n");print();break;}case 'q':return 0;}}return 0; }

 

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