拼音显示数字之和
在pat上面看到的一道题
代码如下:
using namespace std; void output(int num) {int zonghe[10];char *name[]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};int i;for (i = 0; num>=10; i++){zonghe[i]=num%10;num=num/10;}zonghe[i++]=num;while (i--){if (i!=0){cout<<name[zonghe[i]]<<" ";}else{cout<<name[zonghe[i]];}}} int _tmain(int argc, _TCHAR* argv[]) {char n[100];char *p=n;int sum=0;int i=0;cin>>n;while (*p!='\0'){sum=sum+(*p-'0');p++;} //获得数字之和cout<<sum;output(sum); //调用函数return 0; }
用户输入一串数字,获得数字之和,并用拼音显示出来,
在每个拼音之间用“ ”连接,最后一个没有空格
例如,输入123456789,输出si wu代码如下:
using namespace std; void output(int num) {int zonghe[10];char *name[]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};int i;for (i = 0; num>=10; i++){zonghe[i]=num%10;num=num/10;}zonghe[i++]=num;while (i--){if (i!=0){cout<<name[zonghe[i]]<<" ";}else{cout<<name[zonghe[i]];}}} int _tmain(int argc, _TCHAR* argv[]) {char n[100];char *p=n;int sum=0;int i=0;cin>>n;while (*p!='\0'){sum=sum+(*p-'0');p++;} //获得数字之和cout<<sum;output(sum); //调用函数return 0; }
转载于:https://www.cnblogs.com/ZyCoder/p/6043732.html
总结
- 上一篇: iOS -数据库网络之xml解析之远程解
- 下一篇: 【20161109】noip模拟赛