题目内容

题目来源：LeetCode

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

题目思路

这个题目是倒序存储了两个数字，然后模拟进行加法运算。

本题中需要学习到的知识有：

1. 分别使用/和%来代表进位符号flag和当前位的值value

2. 成立哑结点（头结点），这样可以方便很多。

Python代码

# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = Noneclass Solution(object):def addTwoNumbers(self, l1, l2):""":type l1: ListNode:type l2: ListNode:rtype: ListNode"""if not l1 and not l2:returnif not l1:return l2if not l2:return l1dummy=ListNode(-1)p=dummyflag=0while l1 and l2:value=(l1.val+l2.val+flag)%10p.next=ListNode(value)p=p.nextflag=(l1.val+l2.val+flag)/10l1=l1.nextl2=l2.nextwhile l1:value=(l1.val+flag)%10p.next=ListNode(value)p=p.nextflag=(l1.val+flag)/10l1=l1.nextwhile l2:value=(l2.val+flag)%10p.next=ListNode(value)p=p.nextflag=(l2.val+flag)/10l2=l2.nextif flag>0:p.next=ListNode(flag)return dummy.next

 

转载于:https://www.cnblogs.com/chengyuanqi/p/7136826.html

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