c# 字节十六进制转十进制_用C中的十进制,八进制和十六进制数字初始化字节数组...
c# 字节十六进制转十进制
C中的字节数组 (byte array in C)
In C programming language, an unsigned char type can be used to declare byte array in C programming language. An unsigned char can contain a value from 0 to 255, which is the value of a byte.
在C编程语言中, 无符号char类型可用于声明C编程语言中的字节数组 。 无符号字符可以包含0到255之间的值,该值是一个字节的值。
In this example, we are declaring 3 arrays – arr1, arr2, and arr3, arr1 is initialising with decimal elements, arr2 is initialising with octal numbers and arr3 is initialising with hexadecimal numbers.
在此示例中,我们声明了3个数组-arr1 , arr2和arr3 , arr1用十进制元素初始化, arr2用八进制数初始化, arr3用十六进制数初始化。
Example:
例:
#include <stdio.h>int main() {//declaring array, initialising with decimal values unsigned char arr1[]={10, 20, 30, 40, 50};//declaring array, initialising with octal values unsigned char arr2[]={010, 077, 023, 045, 057}; //declaring array, initialising with hexadecimal values unsigned char arr3[]={0x10, 0xAA, 0x67, 0xA1, 0xFF}; int i;//printing the numbersprintf("arr1...\n");for(i=0; i<5; i++)printf("%d ",arr1[i]);printf("\n");//printing the numbersprintf("arr2...\n");for(i=0; i<5; i++)printf("%o ",arr2[i]);printf("\n");//printing the numbersprintf("arr3...\n");for(i=0; i<5; i++)printf("%X ",arr3[i]); printf("\n");return 0; }Output
输出量
arr1... 10 20 30 40 50 arr2... 10 77 23 45 57 arr3... 10 AA 67 A1 FF翻译自: https://www.includehelp.com/c-programs/initialising-byte-array-with-decimal-octal-and-hexadecimal-numbers-in-c.aspx
c# 字节十六进制转十进制
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